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41w^2-31w=0
a = 41; b = -31; c = 0;
Δ = b2-4ac
Δ = -312-4·41·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-31}{2*41}=\frac{0}{82} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+31}{2*41}=\frac{62}{82} =31/41 $
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